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Test WGU Data-Management-Foundations Collection | Study Data-Management-Foundations Group

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WGU Data Management – Foundations Exam Sample Questions (Q58-Q63):

NEW QUESTION # 58
What is shown on the "many" side of a relationship between two tables?

A. Binary relationship
B. Reflexive relationship
C. Weak entity
D. Foreign key

Answer: D

Explanation:
In aone-to-many (1:M) relationship, theforeign keyis placed in thetable on the "many" sideto establish the relationship with theprimary keyof the "one" side.
Example Usage:
A screenshot of a computer AI-generated content may be incorrect.

CREATE TABLE Departments (
DeptID INT PRIMARY KEY,
DeptName VARCHAR(50)
);
CREATE TABLE Employees (
EmpID INT PRIMARY KEY,
Name VARCHAR(50),
DeptID INT, -- Foreign key on the "many" side
FOREIGN KEY (DeptID) REFERENCES Departments(DeptID)
);
* Eachdepartmentcan havemany employees# DeptID is aforeign keyin Employees.
Why Other Options Are Incorrect:
* Option A (Reflexive relationship) (Incorrect):Refers tounary (self-referential) relationships, not 1:
M relationships.
* Option B (Binary relationship) (Incorrect):A binary relationship involvestwo entities, but does not define where the foreign key is stored.
* Option C (Weak entity) (Incorrect):Weak entitiesdepend on a strong entity, but not all "many" sides are weak entities.
Thus, the correct answer isForeign key, as it is placed on the "many" side of the relationship.

NEW QUESTION # 59
Which command is used to filter group results generated by the GROUP BY clause?

A. REPLACE
B. WITH
C. WHERE
D. HAVING

Answer: D

Explanation:
TheHAVINGclause is used in SQL to filtergrouped resultsgenerated by the GROUP BY clause. Unlike WHERE, which filters individual rowsbeforegrouping, HAVING filtersafter aggregationhas been performed.
Example Usage:
sql
SELECT Department, AVG(Salary) AS AvgSalary
FROM Employees
GROUP BY Department
HAVING AVG(Salary) > 50000;
* This query first groups employees by Department, calculates theaverage salary per department, and then filters onlythose departments where the average salary is greater than 50,000.
Why Other Options Are Incorrect:
* Option A (REPLACE) (Incorrect):Used for string substitution, not filtering.
* Option C (WITH) (Incorrect):Used inCommon Table Expressions (CTEs), not for filtering.
* Option D (WHERE) (Incorrect):Used forrow-level filtering before aggregation, but itcannot be used on aggregate functions like SUM() or AVG().
Thus,HAVING is the correct answerfor filtering after grouping.

NEW QUESTION # 60
Which expression can be used to create a temporary name for a table?

A. ALIAS
B. NEW
C. UNION
D. HAVING

Answer: A

Explanation:
Analiasis used in SQL to give atemporaryname to a table or column within a query. It makes queries more readable and helps in cases where a table needs to be referenced multiple times (e.g., in aself-join).
Example Usage:
sql
SELECT e.Name, d.DepartmentName
FROM Employees AS e
JOIN Departments AS d
ON e.DeptID = d.ID;
* Here,Employees is aliased as eandDepartments as d, making the query shorter and clearer.
Why Other Options Are Incorrect:
* Option A (HAVING) (Incorrect):Used to filter grouped results, not create aliases.
* Option B (NEW) (Incorrect):Not a valid SQL keyword for aliasing.
* Option D (UNION) (Incorrect):Combines result sets but does not rename tables.
Thus, the correct answer isALIAS, which allows fortemporary naming of tables or columns.

NEW QUESTION # 61
Which operator defines the field that the index is using in a CREATE TABLE statement?

A. ON
B. UNIQUE
C. IN
D. CHECK

Answer: A

Explanation:
TheONkeyword specifies the field used by anindexwhen creating it in SQL.
Example Usage:
sql
CREATE INDEX idx_employee_name
ON Employees(Name);
* Here, an indexidx_employee_nameis createdon the Name column.
* Thisimproves query performancewhen filtering by Name.
Why Other Options Are Incorrect:
* Option B (IN) (Incorrect):Used in queries to match values in a set, not for indexing.
* Option C (UNIQUE) (Incorrect):Ensures a column has unique values but doesnot define an index field.
* Option D (CHECK) (Incorrect):Used forvalidating column values, not for indexing.
Thus, the correct answer isON, as it defines thecolumn on which an index is created.

NEW QUESTION # 62
How is the primary key indicated in a table?

A. By using a diamond symbol inserted into the table
B. By using an SQL keyword
C. By using bold typeface in the appropriate column
D. By using a formula in SQL

Answer: B

Explanation:
In SQL, aprimary key is explicitly defined using the PRIMARY KEY keywordwhen creating a table.
Example Usage:
sql
CREATE TABLE Products (
ProductID INT PRIMARY KEY,
Name VARCHAR(100),
Price DECIMAL(10,2)
);
* Here,PRIMARY KEY is the SQL keyword that designates ProductID as the primary key.
Why Other Options Are Incorrect:
* Option A (Formula in SQL) (Incorrect):SQLdoes not use formulas to define primary keys.
* Option C (Bold typeface) (Incorrect):SQL syntax does not rely on text formatting.
* Option D (Diamond symbol) (Incorrect):ER diagramsmight use symbols, but SQLdoes not use diamonds to indicate keys.
Thus, the correct answer isSQL keyword, as primary keys are explicitly defined using PRIMARY KEY.

NEW QUESTION # 63
......

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